Typed int with ref equality

[antonmedv]

          Can I get the pointer value of the struct Env?

Playground：https://go.dev/play/p/WIj3_3NoR2z

package main

import (
	"fmt"

	"github.com/expr-lang/expr"
)

type ModeEnum int

const (
	ModeEnumA ModeEnum = 1
	ModeEnumB ModeEnum = 2
)

type Env struct {
	Mode *ModeEnum
}

func main() {
	code := `Mode == 1`

	tmp := ModeEnumA

	env := map[string]any{
		"Mode": &tmp,
	}

	program, err := expr.Compile(code, expr.Env(env))
	if err != nil {
		panic(err)
	}

	output, err := expr.Run(program, env)
	if err != nil {
		panic(err)
	}

	fmt.Println(output)
}

It prints false, but the expectation is true

Originally posted by @Cassius0924 in #154 (comment)

[Cassius0924]

If it is repaired, should the Mode be wrapped with an int function? like:

	code := `int(Mode) == 1`

Or will Mode be converted implicitly?

	code := `Mode == 1`

[Cassius0924]

Is it possible to add a parameter to control whether implicit conversion is performed?

[antonmedv]

The problem is with typed int field. Expr see it as an int and assumes no deref is needed. I think we can try to make type checker more advance.

[Cassius0924]

Are you already fixing it?

[antonmedv]

I finally did it! I also added tests for each builtins in Expr! So now it will work same as in Go itself.