Use console.debug() instead of console.log() where available (e.g. browsers)

[Qix-]

Currently debug output in the browser gets console.log()'d.

However, browsers have a console.debug() call (nonexistent in Node.js, of course) that would group all debug output into its own category, perhaps making it easier for debugging in the browser when trying to look at regular application output.

Relevant lines:

https://github.com/visionmedia/debug/blob/master/src/browser.js#L112-L114

Thoughts?

[picwellwisher12pk]

I am very new with this things. can you guide me a little how I can use debug on browser? I am using Webpack to make a Firefox addon. Any help is appreciated.

[Qix-]

@picwellwisher12pk that has absolutely nothing to do with this ticket. Please open a new one.

[nmccready]

I doubt this will ever happen. The if you want to extend you're console or logger then that is the entire purpose of this library.

https://github.com/nmccready/preacher

You're asking this library to do too much. Keep it the way it is unixy.

[Qix-]

@nmccready I don't see how your response is relevant at all. We're already using console.log() everywhere. I'm simply suggesting the use of console.debug() in the browser instead, since it's available there and would allow people to better filter out log messages using inspector tools.

Since I'm not getting much intelligible feedback on this, I don't see any objections and I think it's an improvement to better match how the behavior works in the console.

[nmccready]

10-4, sorry I thought you were asking to override console.debug with debug itself. Instead your asking for the implementation of debug to use console.debug and not console.log for its output. Apologies

[targos]

console.debug() is available in Node from version 8, and would also be filterable with inspector tools if node is run with --inspect.

[Qix-]

@targos TIL. Yeah I figured the logic would be (console.debug || console.log)(...).

[Qix-]

Actually, the node version uses stdout. If people want to use console.debug, they should see #556.