Closed
Description
When using the following sketch:
void setup() {
Serial.begin(9600);
while (!Serial);
Serial.println("aX,aY,aZ");
Serial.println(); // <-- without this line the labels are fine
}
void loop() {
Serial.print("0,0,0");
Serial.println();
delay(1000);
}
The aX
label is lost in the Serial plotter:
If the Serial.println();
line in setup is removed, all is good.